how to make nxn matrix

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WonJong We
WonJong We 2021-4-14
评论： WonJong We 2021-4-15
I want to make nxn matrix by follweing rule
n=input
first and last is 1
how can do it?
This is the original formula.
clc;
n=input
A=(n ; n)???
  2 个评论
Walter Roberson
Walter Roberson 2021-4-14
Sorry, that image is too faint to read.
WonJong We
WonJong We 2021-4-14
Thank you for the information.
I will change!!

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采纳的回答

Walter Roberson
Walter Roberson 2021-4-14
Ran in:
n = 7
n = 7
d = ones(1,n-2)/2;
M = zeros(n,n) + diag([0,d],+1) + diag([d,0],-1);
M(1) = 1; M(end) = 1;
M
M = 7×7
1.0000 0 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0 1.0000
  9 个评论
显示 7更早的评论
Walter Roberson
Walter Roberson 2021-4-15
Ran in:
n=3;
%n=input ('put your n=')
d = ones(1,n-1)/2;
M = zeros(n+1,n+1) + diag([0,d],+1) + diag([d,0],-1);
M(1) = 1; M(end) = 1;
M
M = 4×4
1.0000 0 0 0 0.5000 0 0.5000 0 0 0.5000 0 0.5000 0 0 0 1.0000
T = [sym('T0') ; sym('T',[n 1]) ]
T = 
Tvals = T;
Tvals(1) = 500;
Tvals(n+1) = 300; %Tn is at position n+1
MT = subs(M*T, T, Tvals)
MT = 
eqn = MT == T
eqn = 
sol = solve(eqn)
sol = struct with fields:
T0: [1×1 sym] T1: [1×1 sym] T2: [1×1 sym] T3: [1×1 sym]
sol.T0
ans = 
500
sol.T1
ans = 
sol.T2
ans = 
sol.T3
ans = 
300

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