how can I Compute the value of d for the following values of x , Outcome equation d=((34.63/x)-5.126)/2.54

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Hamada Alkhlif
Hamada Alkhlif 2021-4-15
评论： Steven Lord 2021-4-15
Is my code right i am beginner in matlab.
>>clc
>>clear
for x=[0.1000,0.1500,0.2000]
fprintf("\n\t%g\n",x)
else d=((34.63/x)-5.126)/2.54
disp ("ANSWER")
end
"OUTCOME WANTED RESULT "

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回答（2 个）

DGM
DGM 2021-4-15
编辑：DGM 2021-4-15
I have no idea what that code is intended to do, but if you just want to evaluate the expression all x:
x=[0.1000,0.1500,0.2000]
d=((34.63./x)-5.126)/2.54
I guess if you're trying to get it to display formatted results to console, you could do that as well.
for l=1:numel(x)
fprintf('\t%g\t%g\n',x(l),d(l))
end
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Hamada Alkhlif
Hamada Alkhlif 2021-4-15
编辑：Hamada Alkhlif 2021-4-15
actually iam getting the answer right but it look deferent .
answer after submitte above code :
>> Untitled3
0.1 134.32
answer =
0.1000 134.3205
0.1500 88.8743
0.2000 66.1512
0.15 88.8743
answer =
0.1000 134.3205
0.1500 88.8743
0.2000 66.1512
0.2 66.1512
answer =
0.1000 134.3205
0.1500 88.8743
0.2000 66.1512
>>
i just want the code to give 1 answer like this
answer =
0.1000 134.3205
0.1500 88.8743
0.2000 66.1512
how can i modify the last code @DGM ?
Steven Lord
Steven Lord 2021-4-15
Every time this line of code executes:
answer=[x' d']
it assigns a value to the variable named answer then displays the contents of that variable. If you just want to assign a value to the variable but not display it, end the line of code with a semicolon.
answer=[x' d'];
Then if you want to display it at the end of the code you can.
disp(answer) % or just plain
answer

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VBBV
VBBV 2021-4-15
编辑：VBBV 2021-4-15
%true
d = [];
for x=[0.1000,0.1500,0.2000]
d=[d ((34.63/x)-5.126)/2.54];
disp ("ANSWER");
end
x=[0.1000 0.1500 0.2000];
fprintf("\t%4g\t\t%4g\n",[x;d])
  2 个评论
Hamada Alkhlif
Hamada Alkhlif 2021-4-15
this is almost the wanted code just is that the x values not in 4 decimals and it the code out put display 3 words of answers ,it required only one .
VBBV
VBBV 2021-4-15
编辑：VBBV 2021-4-15
d = [];
for x=[0.1000,0.1500,0.2000]
d=[d ((34.63/x)-5.126)/2.54];
end;
disp ("ANSWER");
x=[0.1000 0.1500 0.2000];
fprintf("\t%.4f\t\t%.4f\n",[x;d])
Try this

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