Solution
When you call the original function, you do so with
original_function(arg1,arg2,arg3,arg4,..)
Using varargin lets you pass any number of arguments by making a cell array
varargin = {{arg1},{arg2},{arg3},{arg4},..} % A 1xN cell array
The issue is that in the subfunction you are passing one argument -
varargin_new = {{new_arg1},{new_arg2},{new_arg3},{new_arg4},..} % A 1xM cell array
subfunction(varargin_new) % Giving only one argument, varargin_new
to varargin instead of passing separate arguments. This means that in the subfunction, your new varargin is
varargin = {{{new_arg1},{new_arg2},{new_arg3},{new_arg4},..}} % A 1x1 cell array
You can solve this by changing the expected input of the subfunction to the argument you are passing. Since you are using a single cell array instead of an unknown number of parameters, you don't need to use varargin at all.
Example
function output_A = function_A(varargin) % I don't know how many inputs will be passed to this
% function, so I use varargin to accomodate any number of inputs
new_varargin = changes_to(varargin); % Placeholder for whatever is in this function
output_A = function_B(new_varargin);
end
function output_B = function_B(input) %Note that I am not using varargin
% because I know there is exactly one input (even if I don't know what size
% that input is)
output_B = changes_to(input); % Placeholder for whatever is in the function
end
