Naming Variable from input arguments

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xplore29
xplore29 2013-6-30
My function takes two input arguments Dim,Snr I want to name my variable based on these two arguments in the following manner
Matrix_Dim{Snr}
for example if Dim=4, Snr=3 My cell variable should be named Matrix_4
Matrix_4{3}=somexyz where somexyz is the output which i want to store in Martix_4{3}
eval(['matrix_' num2str(DIM) '= somexyz']) will not create the cell array which i actually want to do.
how can i do that.

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回答（2 个）

Shashank Prasanna
Shashank Prasanna 2013-6-30
Try using {somexyz} instead of somexyz so that it is a cell.
Walter Roberson
Walter Roberson 2013-6-30
  2 个评论
xplore29
xplore29 2013-6-30
Thank you for the reference. I saw this post before posting the question. This post addresses the issue of assigning result to appropriate cell locations and does not talk about naming the variable dynamically. In my case, I have to first name the variable dynamically and then assign the result in the appropriate cell. I know how to do these two things separately. The problem comes when i try to do these two together.
Walter Roberson
Walter Roberson 2013-6-30
编辑：Image Analyst 2013-6-30
Don't do it.
Matrix{Dim}{Snr} = somexyz; %cell array
or
Matrix(Dim).Snr(Snr) = somexyz; %structure
Building variable names on the fly will always get you in trouble.
If you need the variable names to be separate for the purposes of save() then still do not construct the variable names on the fly. Instead,
matrices.(sprintf('matrix_%d', DIM)){Snr} = somexyz;
and then
save('FileName.mat', '-struct', 'matrices')
The post does address naming variables dynamically: it says DON'T, and shows the alternatives. And if you read it right through, it does show a way it can be done in the quite rare circumstance that it is needed.

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