Extract columns into new variables efficently

8 次查看(过去 30 天)
Hi Mathwork's community,
So I have a Matrix A such as:
A= [1 1 2 2 3 3 1 1 2 2 3 3; 1 1 2 2 3 3 1 1 2 2 3 3];
And a matrix B, which is the matrix that I'd like to separate into three different variables. (Note: There will always be three variables).
B = [10 20 30 40 50 60 70 80 90 100 110 120; 1 2 3 4 5 6 7 8 9 10 11 12];
Variable1 corresponds to B positions where A values are equal to 1, Variable2 corresponds to B positions where A values are equal to 2 and Variable3 corresponds to B positions where A values are equal to 3. The expected output should be:
Variable1 =[10 20 70 80; 1 2 7 8]
Variable2 = [30 40 90 100 ; 3 4 9 10]
Variable3 = [50 60 110 120; 5 6 11 12]
Could somone please help me out?
Santos
  2 个评论
Walter Roberson
Walter Roberson 2021-4-21
What do you want to have happen for the case where the first row of A has a different value than the corresponding position in the second row of A?
Will the three unique values in A always be 1, 2, and 3, or could it be (for example) 7, 29, 31 ? Negatives? Fractions?
Santos García Rosado
Hello Walter. Thank's for the question. Clearly, I didn't make my-self clear enoguh on that part. All the rows of A will be equal to the first row and will always be 1, 2 and 3 values.

请先登录,再进行评论。

采纳的回答

Jeff Miller
Jeff Miller 2021-4-21
A= [1 1 2 2 3 3 1 1 2 2 3 3; 1 1 2 2 3 3 1 1 2 2 3 3];
B = [10 20 30 40 50 60 70 80 90 100 110 120; 1 2 3 4 5 6 7 8 9 10 11 12];
type1 = A(1,:) == 1;
Variable1 = B(:,type1);
% et cetera

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

产品


版本

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by