removing trailing zeros at the end of floating number
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I m getting the numerical result with trailing zeros even after rounding of to few decimal places for eg.:- 3.265000000000 how do i remove those zeroes and just get the value as 3.265
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DGM
2021-4-21
编辑:DGM
2021-4-21
Assuming this is for display purposes, try something like
fprintf('%6.3f\n',3.2653246546516)
gives
3.265
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James Tursa
2021-4-21
编辑:James Tursa
2021-4-21
The trailing 0's is an artifact of converting the binary floating point bit pattern into a decimal number for display purposes, so this is just a display issue. The number isn't stored in decimal so those decimal 0's you are worried about don't exist in the stored number. The stored number is using IEEE binary floating point format, not any decimal format. What are you doing with these numbers downstream in your code where you think these trailing 0's will cause you a problem?
Also, many decimal numbers can't be represented exactly in binary floating point anyway. So if you were to print out many more digits, there will be non-zero digits after some trailing 0's in the decimal conversion. This is the nature of using binary floating point for calculations.
Adam Danz
2021-4-21
format long
x = -3.265000000000;
str = sprintf('%g\n',x)
x = -3.2650000000001;
str = sprintf('%g\n',x)
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