Bode Plot and resonant peaks

6 次查看（过去 30 天）
Khadija Sulail
Khadija Sulail 2021-4-21
回答： MULI 2024-5-28
Hello,
I'm trying to fit these points to get a bode plot and possible transfer function
w = [0.1 0.2 0.3 0.5 0.8 1 2 3 5 8 10 20 30 50 80 100 200 300 500 800 1000 2000 3000 5000 8000];
G = [0 0 0 0 0 0 0 10 22 28 33 38 35 33 30 28 20 14 8 0 0 0 0 0 0];
I know there is a zero at 2 and the increasing is steeper so started with
"s^2+4*s+4" on the numerator
I know there is a resonant peak at x = 20 but I'm unable to do it.
Also. how to make the bode plot stop at 0 ?
you can find my try here with this transfer function :H=((s^2+4*s+4))/((s+30)^3);
with C = 6750

请先登录，再回答此问题。

回答（1 个）

MULI
MULI 2024-5-28
I understand that you are trying to get bode plot with the given data.
You may follow these suggestions:
  • There is a zero at s=0 and order can be found by calculating slope of line.
  • From the transfer since there is decrease in slope at resonant frequency i.e s=20 there is a pole at s=20, to get order of poles can be found by taking the slope of line.
  • Again at s=800 there is change is slope so there is a possibility of zero at that frequency.
After getting the right transfer function you may use the function ‘bode’ to get bode plot.
You may refer to this documentation link for more information on ‘bode’ function.
https://www.mathworks.com/help/releases/R2021a/ident/ref/lti.bode.html

类别

在 Help Center 和 File Exchange 中查找有关 Frequency-Domain Analysis 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by