indexing diagonals out of a 3d matrix

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Alberto Navarro
Alberto Navarro 2013-7-9
I thought this would be fairly simple. I thought the diag function should be able to do this task. I have a 14x14x1045 matrix Ht, t=1,...,1045 simbolizes the number of observations. I merely want to extract the main daigonals of Ht for all t and store them in a new 3d matrix Dt which is also 14x14x1045 which contains the diagonal elements of every Ht and zeros in all other positions. However, when using the function diag(Ht) I get the following error: Error using diag First input must be 2D.
Is there a function that works like diag but for 3d matrices? I have no experience programing any functions. Could someone please provide a simple loop to make a function that fulfills this task in case no such function exists already?
I´m sorry if this question is too trivial, but I haven´t been able to find a specific answer and I seem not to be able to program such a function with my expertise level...
Thanks a lot for your help!

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采纳的回答

Matt J
Matt J 2013-7-9
编辑：Matt J 2013-7-9
D=bsxfun(@times, eye(size(H(:,:,1))), H)
  2 个评论
Matt J
Matt J 2013-7-9
编辑：Matt J 2013-7-9
You could also use ndSparse (Available Here) to improve memory efficiency,
D=bsxfun(@times, ndSparse(speye(size(H(:,:,1)))), H);
Alberto Navarro
Alberto Navarro 2013-7-9
Great! Thanks a lot for the super fast and efficient answer!
Best regards!

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更多回答（2 个）

Evan
Evan 2013-7-9
编辑：Evan 2013-7-9
A = rand(14,14,1045);
B = A(logical(repmat(eye(size(A(:,:,1))),[1 1 size(A,3)])))
Kiran Sagar
Kiran Sagar 2013-7-9
I think this would work elegantly. But I don't know if this would take up alot of time/memory for your purposes.
for i=1:1045
Dt(:,:,i)=diag(diag(Ht(:,:,i)));
end
  1 个评论
Alberto Navarro
Alberto Navarro 2013-7-9
Memory/time wasn´t an issue. That worked fine as well. I solved it with the first answer, but with this one, I now know how to use the for loop in the command window. Thanks for the suggestion!

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