Oh no! A(A==0)=NaN is turning my matrix into all zeros!!

2 次查看（过去 30 天）
Kate
Kate 2013-7-12
Okay, I'm feeling like an idiot, what on earth could I be doing wrong?
>> whos KoppenDsb_airT
Name Size Bytes Class Attributes
KoppenDsb_airT 360x720x361 374284800 single
>> min(min(KoppenDsb_airT))
ans(:,:,1) =
-26.5479
ans(:,:,2) =
-23.5349
ans(:,:,3) =
-22.6819
ans(:,:,4) =
-17.3890
ans(:,:,5) =
-12.0117
ans(:,:,6) =
-8.7705
ans(:,:,7) =
-5.3165
ans(:,:,8) =
0
ans(:,:,9) =
0
etc...
KoppenDsb_airT(KoppenDsa_airT==0)= nan;
>> min(min(KoppenDsb_airT))
ans(:,:,1) =
0
ans(:,:,2) =
0
ans(:,:,3) =
0
ans(:,:,4) =
0
ans(:,:,5) =
0
ans(:,:,6) =
0
ans(:,:,7) =
0
ans(:,:,8) =
0
ans(:,:,9) =
0
etc...
Any idea what I'm doing wrong? Thanks!

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采纳的回答

the cyclist
the cyclist 2013-7-12
编辑：the cyclist 2013-7-12
I think you may be mixing up your variables
KoppenDsa_airT
and
KoppenDsb_airT
Still, the result is puzzling to me.
Is the array the same shape after that operation?
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Kate
Kate 2013-7-12
Another question: I'm trying to look at my whole KoppenDsb (monthly data) over my 30 year climate period.
KoppenDsb_airT(KoppenDsb_airT==0)= nan;
Dsb_airT_climatology=mean(reshape(KoppenDsb_airT,[],361),1);
but now my min and max are NaN's. Is there a better way to do this?
Matt Kindig
Matt Kindig 2013-7-12
If you have the Statistics toolbox installed, you can you nanmean() to take the mean and ignore NaN's.
doc nanmean

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