Any ideas to find intersection between tan(t) and y1, y2, and y3 line equations?

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Mohammed Sayan
Mohammed Sayan 2013-7-14
Hello! I want to find intersection between tan(t) and the following line equations but my code instead of giving me two intersection points, just giving me one at origin(0,0)
t=0:0.01:5;
y1=0.5*t; y2=t; y3=2*t;
i1=intersect(tan(t),y1)
i2=intersect(tan(t),y2)
i3=intersect(tan(t),y2)
HINT: There should be 2 intersection points for each one of i1, i2, and i3!

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采纳的回答

Mohammed Sayan
Mohammed Sayan 2013-7-14
ieq1=@(t) tan(t)-0.5*t;
ieq2=@(t) tan(t)-t;
ieq3=@(t) tan(t)-2*t;
i1=fzero(ieq1,[pi 3*pi/2]);
i2=fzero(ieq2,[pi 3*pi/2]);
i31=fzero(ieq3,pi/4);
i32=fzero(ieq3,[pi 3*pi/2]);

更多回答（1 个）

Matt J
Matt J 2013-7-14
I assume you are looking for solutions on [-pi/2, pi/2].
The only one of the functions that has an intersection anywhere there but t=0 is y2. You can find the positive solution using fzero,
>> fun=@(t) tan(t)-2*t; [T,fval]=fzero(fun,3*pi/8)
T =
1.1656
fval =
4.4409e-16
The other solution is -T, due to the symmetry of the functions.

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