Building matrix using vectors?Easy question.
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P{1}, P{2}...P{n} are my vectors.
And I want P{1} is first row of my matrix.P{2} second row of my matrix. How can I do this?
采纳的回答
Iain
2013-7-19
Depending what you have:
1) matrix = [row_vector1;row_vector2; ... row_vectorn];
2) matrix = [col_vector1, col_vector2, ... col_vectorn]';
3) matrix(row_number1,:) = vector1;
matrix(row_number2,:) = vector2;
matrix(row_number3,:) = vector3;
更多回答（2 个）
Jos (10584)
2013-7-19
编辑：Jos (10584)
2013-7-19
Your question suggests you have a cell array with vectors, so you can/should make use of comma-separated list expansion. If all vectors are of the same length, take a look at CAT
P = {1:3,11:13,21:23} % row vectors
M = cat(1,P{:})
If they have different lengths, you might be interested in PADCAT, which pads the vectors with NaNs
P = {[1:3].' , [11:15],' , [21:24],'} % column vectors
M = padcat(P{:}) ;
heybatollah jokar
2013-7-19
*assume you have n vectors with same length which stored in P as follows: P={[vector 1],[vector 2],[vector 3],...}
now using simple code:*
for i=1:length(P)
A(i,:)=P{i}
end
as an example %================================
clc clear all P={[1 2 3],[4,5,6],[7 8 9]}; for i=1:length(P)
A(i,:)=P{i};
end
disp(A) %==============================
% result:
1 2 3
4 5 6
7 8 9
1 个评论
Jos (10584)
2013-7-19
why use a for-loop if you have CAT ... (see the answer above for an example)
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