Fourier Series using MATLAB

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MathWizardry
MathWizardry 2021-5-11
回答： Paul 2021-5-11
MATLAB CODE:
syms x
n=1:1;
k=1*n;
L=pi;
f1(x)=piecewise(x>pi&<0,-x-pi;x>0&<pi,x+i);
a1=int(f1(x),x,-L,L);
a0=a1/(2*pi);
ak=it(f1(x)*cos(k*x),x,-L,L);
bk=int(f1(x)*sin(k*x),x,-L,L);
a=ak/pi;
b=bk/pi;
F1=a0+sum(a.*(cos(k*pix/L))+b.*(sin(k*pi*x/L)));
please correct my codes.
it says that:
f1(x)=piecewise(x>pi&<0,-x-pi;x>0&<pi,x+i);
↑
Invalid use of operator.

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回答（1 个）

Paul
Paul 2021-5-11
You probably want
f1(x) = piecewise(x < -sym(pi), 0,x < 0,-x-sym(pi), x<=sym(pi), x+sym(pi), x>sym(pi), 0);
You'll find some other typos in your code, like using "it" instead of "int" in the equation for ak and pix instead of pi*x in the equation for F1.
Recommend defining
syms L
L = sym(pi)
and then use L everywhere instead of pi.

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