Array indexes must be positive integers or logical values.

Question

ljaseon 2021-5-12

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/828455-array-indexes-must-be-positive-integers-or-logical-values

评论： ljaseon 2021-5-12

采纳的回答： Alan Stevens

在 MATLAB Online 中打开

this is the code that what i input but

Array indexes must be positive integers or logical values. at the moment SUM= E1*SUM(V(3:IOUT+1,JOUT+2))....

+E1*V(2,JOUT+2)/2+E2*V(IOUT+2,2)/2;

what is the problem?

clear all;format compact;
%Output;
%
%     H      NT      Zo
%  -----------------------
%   0.25    700    69.77
%   0.1     500    65.75
%   0.05    500    70.53
%   0.05    700    67.36
%   0.05   1000    65.50
H=0.05;
NT= 100;
A=2.5; B=2.5; D=0.5; W=1.0;
ER=2.35;
EO=8.81E-12;
U=3.0E+8;
NX=A/H;
NY=B/H;
ND=D/H;
NW=W/H;
VD=100.0;
ERR=1.0;
    E1=EO;
    E2=EO*ERR;
   
%CALCULATE CHARGE WITH AND WITHOUT DIELECTRIC
 L=1:2
    E1=EO;
    E2=EO*ERR;
    
%INITIALIZATION
    V=zeros(NX+2,NY+2);
    
%SET POTENTIAL ON INNER CONDUCTOR(FIXED NODES) EQUAL TO VD 
V(2:NW+1,ND+2)=VD;
    
   
     %NOW,CALCULATE THE TOTAL CHARGE ENCLOSED IN A 
     %RECTANGULAR PATH SURROUNDING THE INNER CONDUCTOR
     
     IOUT=round((NX+NW)/2);
     JOUT=round((NY+ND)/2);
     
     %SUM POTENTIAL ON INNER AND OUTER LOOPS
     for K=1:2
         SUM=0;
         SUM= E1*SUM(V(3:IOUT+1,JOUT+2))....
             +E1*V(2,JOUT+2)/2+E2*V(IOUT+2,2)/2;
         for J=1:JOUT-1
             if(J<ND)
                 SUM=SUM+E2*V(IOUT+2,J+2);
             elseif(J==ND)
                 SUM=SUM+(E1+E2)*V(IOUT+2,J+2)/2;
             else
                 SUM=SUM+E1*V(IOUT+2,J+2);
             end
         end
         if K==1
             SV(1)=SUM;
         end
         IOUT=IOUT-1;
         JOUT=JOUT-1;
     end
     SUM=SUM+2.0*E1*V(IOUT+2,JOUT+2);
     SV(2)=SUM;
     Q(L)=abs(SV(1)-SV(2));
     ERR=ER;
% FINALLY,CALCULATE Zo
Co=4.0*Q(1)/VD;
C1=4.0*Q(2)/VD;
ZO=1.0/(U*sqrt(C0*C1));
disp([H,NT,ZO])