Can the classifcation learner app and regression apps be used with sequential data?

2 次查看(过去 30 天)
Sorry if this is a basic question but i find it hard to locate any details on what format data needs to be in to work with these apps in the documentation.
I have created a table containing 770 cells where each row has a single cell array in it (770X1). Each cell contained in the table has sequential data (8 rows x 1100 columns).
I added a 2nd column in my table that has the categorical label for each cell. So now my table is 770x2.
When i try to use the regression learner app i get an error saying there is 'no variable suitable as a response' and when i try to use the calssifcation learner app i get an error stating 'No predictor selected'
Is this becuase i am trying to use sequential data contained in cells or am i doing something else incorrect?

采纳的回答

Shashank Gupta
Shashank Gupta 2021-5-24
Hi Christopher,
Classification and regression learner APP does not take cell array as input, thus its not trivial to do a classification or regression on sequential data. Even if you are able to upload the data to learner APP, the existing model in the APP is not suitable for forecasting or dealing with sequencial data. Instead, a better choice would be use LSTM based network. I would recommend you to use Deep learning Designer APP. Check out this link, It will give you a good headstart.
I hope this helps.
Cheers
  1 个评论
CHRISTOPHER MILLAR
CHRISTOPHER MILLAR 2021-5-24
HI,
Thanks for the reply. I thought that this was the case but was just checking. I have already developed an LSTM network i was just going to use the classification learner app as a way of comparing the results using the sequential data.
I have not used the Deep LEarning Designer though so thanks for pointing that out to me. It looks very easy to use
Regards
Chris

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Classification Learner App 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by