how to solve implicit equation with two variables

2 次查看(过去 30 天)
Dear fellows,
I have a function like this pf=f(p1,p2). The problem is "pf" is a vecotor so in fact there are two output for this function, pf(1) and pf(2). And there is not explicit expression for function f. It is a big function and involves a lot of logic compare, etc inside it. I want to solve for p1 and p2 such that pf(1)=1000 and pf(2)=1000. Do you know how to realize this?
Cheers, Xueqi
  6 个评论
Walter Roberson
Walter Roberson 2013-7-31
You are right, sum() could result in accidental zeros. The difficulty with sum(f2(p).^2) is that it will not have 0 crossings, just a single 0 (round-off permitting); if that is acceptable then fminbnd() would likely be a better choice than fsolve()
xueqi
xueqi 2013-8-1
As I see, I think the problem comes from the function are far from smooth. It has numerous local minimum. Probably this is the reason it stuck at the initial point...So I think we should look for some way to get rid of this problem. How does fminbnd work better in this aspect?

请先登录,再进行评论。

回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Solver Outputs and Iterative Display 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by