Use kron to build a matrix

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Jyoti Mangal
Jyoti Mangal 2021-5-24
评论： Stephen23 2021-5-25
Hi,
I would like to build a matrix that resembles something like
A = [-1 1 0 0 0 0 0 0;
0 -1 1 0 0 0 0 0;
0 0 -1 1 0 0 0 0;
0 0 0 -1 1 0 0 0;
0 0 0 0 -1 1 0 0;
0 0 0 0 0 -1 1 0;
0 0 0 0 0 0 -1 1];
Can I use kron function to build something like this? One of the things that needs to be a variable will be the number of rows, so I need my kron function to be flexible such that it can build more such matrices, for eg. a matrix with four such rows would look like
A = [-1 1 0 0 0;
0 -1 1 0 0;
0 0 -1 1 0;
0 0 0 -1 1;]
Also happy to do using any other method than kron. Thank you for your help.

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采纳的回答

Matt J
Matt J 2021-5-24
Ran in:
No, the matrix you've shown is not a Kronecker product, but the matrix is easily generated using diff, e.g.,
A=full(diff(speye(7)))
A = 6×7
-1 1 0 0 0 0 0 0 -1 1 0 0 0 0 0 0 -1 1 0 0 0 0 0 0 -1 1 0 0 0 0 0 0 -1 1 0 0 0 0 0 0 -1 1
  2 个评论
Jyoti Mangal
Jyoti Mangal 2021-5-24
Thank you so much! This worked like a charm
Stephen23
Stephen23 2021-5-25
Ran in:
A = diff(eye(7)) % no need for sparse array
A = 6×7
-1 1 0 0 0 0 0 0 -1 1 0 0 0 0 0 0 -1 1 0 0 0 0 0 0 -1 1 0 0 0 0 0 0 -1 1 0 0 0 0 0 0 -1 1

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更多回答（1 个）

Sulaymon Eshkabilov
Hi,
In you exercise, use eye() and kron(). and then change the necessary element of the generated matrix if necessary.
Good luck

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