Patch won't fill my polygon and inpolygon won't find points inside

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I'm trying to do two things with the coordinates of a shape that was created using slice_stl_create_path from the FEX. First, I just want to plot one of the slices as a filled patch, but I can only get part of it filled. I think it's because it kind of appears as two polygons, but I'm not sure how to avoid that given the method for creating the coordinates. I've attached a file with the x and y coordinates of the polygon as derived from the FEX script.
Second, I have another grid of data and would like to identify points on the grid that are within this polygon. I know from looking at the numbers that some are within it, but inpolygon returns all zeros. The grid points are also in the attachment. Here's some code:
load('coords')
% this doesn't fill anything
patch(hhx,hhz,'k') % hhx and hhz are found with slice_stl_create_path.m
% this fills part of it
[shhx,idx] = sort(hhx);
shhz = hhz(idx);
patch(shhx,shhz,'k')
% to find points inside
inshape = inpolygon(xdim(31:31+length(zdim)-1),zdim,hhx,hhz); % xdim and zdim are the grid points, xdim is longer than zdim
  4 个评论
Cris LaPierre
Cris LaPierre 2021-5-26
编辑:Cris LaPierre 2021-5-26
I tried running your code and got the following errer:
Unrecognized function or variable 'ycoords'.

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采纳的回答

Cris LaPierre
Cris LaPierre 2021-5-27
For question 2, it doesn't work for a couple reasons.
  1. xdim(31:length(zdim)-1) must be the same length as zdim. They are not, so you get an error.
  2. Modifying the data so they are the same length, none of the points fall within the polygon, hence, inpolygon is not returning anything.
load('coords')
% Remove nans
hhx(isnan(hhx)) = [] ;
hhz(isnan(hhz)) = [] ;
% GEt the boundary
idx = boundary(hhx,hhz) ;
hhx = hhx(idx) ; hhz = hhz(idx) ;
patch(hhx,hhz,'k')
hold on
plot(xdim(31:length(zdim)+30),zdim,'r.')
hold off
Perhaps you have not created the grid of data you intended. Can you describe what you expected the gridded points to be?
  2 个评论
Daniel
Daniel 2021-5-27
Apologies. I had a typo that I have now fixed. The lengths were not the issue. Perhaps I need a meshgrid? xdim and zdim are meant to be the x and z coordinates of a grid on which data exist. So all pairs of x and z coordinates should be considered, but I thought that inpolygon did that. Does it not?
Cris LaPierre
Cris LaPierre 2021-5-27
No, it will not create the combinations for you. Look to the documentation.
  • The size of xq must match the size of yq. (and vice versa)
You must pass in the data with all the pairings already made. If you want to create a grid using the points you already have,then yes, use meshgrid.
load('coords')
% Remove nans
hhx(isnan(hhx)) = [] ;
hhz(isnan(hhz)) = [] ;
% GEt the boundary
idx = boundary(hhx,hhz) ;
hhx = hhx(idx) ; hhz = hhz(idx) ;
patch(hhx,hhz,'k')
[xq,yq] = meshgrid(xdim,zdim);
inshape = inpolygon(xq,yq,hhx,hhz);
hold on
plot(xq,yq,'b.')
plot(xq(inshape),yq(inshape),'r.')
hold off

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更多回答(2 个)

KSSV
KSSV 2021-5-27
load('coords')
% Remove nans
hhx(isnan(hhx)) = [] ;
hhz(isnan(hhz)) = [] ;
% GEt the boundary
idx = boundary(hhx,hhz) ;
hhx = hhx(idx) ; hhz = hhz(idx) ;
patch(hhx,hhz,'k')
  1 个评论
Daniel
Daniel 2021-5-27
Thanks for the answer. I had already figured out this part of the question, but I'm leaving it "unanswered" until I get an answer on the second part regarding inpolygon. Can you tell me why that is not working even though some of the grid points (xdim and zdim) in the attachment are within the polygon?

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Matt J
Matt J 2021-5-27
编辑:Matt J 2021-5-27
Aside from what others have said, your hhx and hhz data does not define a polygon, but rather two polygons. I supsect that this will confuse inpolygon() even if you test points that are within one of the polygons.
load coords
pgon=polyshape(hhx,hhz,'Simplify',false);
plot(pgon)
I'm assuming the shape you actually intend is closer to the following:
d=0.0003;
pgon=polybuffer( polybuffer(pgon,d), -d); %morphological close
pgon=rmslivers(pgon,3e-6);
plot(pgon)
  4 个评论
Daniel
Daniel 2021-5-27
Honestly, I'm not totally sure, but that's the less important part. How would you extend this to use inpolygon?
Matt J
Matt J 2021-5-27
You can either use isinterior()
or you can get the vertices from the Vertices property of the polyshape object,
pgon.Vertices
whereupon you can use inpolygon() as normal.

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