Function 'subs': how use?

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JRC 2013-8-21

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I have realized that the counts with this function 'subs' doing x(1) +1*x(2) and x(1) + 1*x(2) are differents, for example. The space in these expressions give me results differents.

Which the problem?

Which is correct? I think that the correct is x(1) +1*x(2) and not with the space.

Thanks.

JRC

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Answer 1

Walter Roberson 2013-8-21

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In the context of the [] operation,

x(1) +1*x(2)

would usually be interpreted as

(x(1)), (+1*x(2))

which is two entries.

x(1) + 1*x(2)

inside [] would be interpreted as one entry.

If you are not within the context of [] then the two should be the same.

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Walter Roberson 2013-8-21

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The remarks I gave for [] apply to {} as well (I forgot about that)

Your

1*x(N-1) -1*u(N-1)

is being interpreted as

1*x(N-1), -1*u(N-1)

Within list-building operations, [] and {}, if you have two expressions separated by a string, and each of the expressions by itself could be interpreted as being a syntactically valid expression, then the space will be interpreted as horizontal concatenation. +1*x(2) is (unary plus 1) multipled by x(2) so that is a valid expression by itself, and x(1) is a valid expression by itself, so x(1) +1*x(2) is interpreted as horzcat(x(1), +1*x(2)). When either or both of the expressions cannot be interpreted as syntactically valid expressions then the space is not interpreted as indicating horizontal concatenation.

Which one is "right" depends on your purpose.

Advice: if you are using spacing at all, always use a space after a + or - that is used to indicate subtraction, and (so that you will find your code easier to read later), use a comma between expressions that you intend to be horizontally concatenated together. If you are machine-generating expressions as strings and for some reason the generated strings might have irregular spacing, then add () around terms that you intend to be a single expression.

[1 -4]

is two elements, not subtract(1,4) or add(1, unaryminus(4))

[(1 -4)]

is subtract(1,4)

Walter Roberson 2013-8-21

Do not eval() MuPAD expressions, such as are returned by sym() or subs(). MuPAD and MATLAB use different syntax rules and different operators. If you want to convert a MuPAD expression into executable MATLAB form, use matlabFunction() on the MuPAD expression -- but if you do not need to execute at the MATLAB level, keep expressions in MuPAD form. If you have a MuPAD expression which consists entirely of constants and you want to convert it to double precision, use double() on the MuPAD expression.

Please see also http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F . It looks to me as if you would be better off storing values in a struct than using eval() to generate new variable names.

JRC 2013-8-21