I have 4 bits combinations, and I want to change the size of the matrix HT depending on these combinations, the description below

Question

Matthew Worker 2021-6-12

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/854510-i-have-4-bits-combinations-and-i-want-to-change-the-size-of-the-matrix-ht-depending-on-these-combin

评论： Rena Berman 2021-12-16

采纳的回答： DGM

First ___ I creat the combinations like the follow:

n=4; %number of bits

r = [ 0:2^n-1 ];

A = [];

for i = 1 : n

A = [A;r];

end

c = [];

for i = 0 : n-1

c = [ 2^i c ];

end

c = c';

B = [];

for i = 1 : 2^n

B = [B c];

end

A=sign(bitand(A,B))'

Second_____

%A matrix has in each row 4 bits : 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111

HT=(n,3); % the rows of HT is equal to the number of bits

When the bit combination is 0001 then HT will have one row (the last one) and When the bit combination is 0110 HT will have two rows (the second and the third one), also I think When the bit combination is 0000 it's better to put HT equal to zero;

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Rena Berman 2021-12-16

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Answer 1

DGM 2021-6-12

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https://ww2.mathworks.cn/matlabcentral/answers/854510-i-have-4-bits-combinations-and-i-want-to-change-the-size-of-the-matrix-ht-depending-on-these-combin#answer_723170

编辑：DGM 2021-6-12

Not sure how you want to handle HT, but here goes:

n = 4; %number of bits
% don't need all those loops
A = dec2bin(0:2^n-1)=='1' % should be in base toolbox
A = 16×4 logical array
   0   0   0   0
   0   0   0   1
   0   0   1   0
   0   0   1   1
   0   1   0   0
   0   1   0   1
   0   1   1   0
   0   1   1   1
   1   0   0   0
   1   0   0   1
% assuming HT already exists
HT = randi(9,n,3)
HT = 4×3
     9     7     2
     3     9     5
     3     2     7
     4     5     4
% idk how you want to handle a bunch of different-sized arrays
% i'm just going to throw them all in one cell array
HT_out = cell(size(A,1),1);
for r = 1:size(A,1)
    thisHT = HT(A(r,:),:);
    if isempty(thisHT)
        HT_out{r} = [0 0 0];
    else
        HT_out{r} = thisHT;
    end
end
format compact
celldisp(HT_out)
HT_out{1} =
     0     0     0
HT_out{2} =
     4     5     4
HT_out{3} =
     3     2     7
HT_out{4} =
     3     2     7
     4     5     4
HT_out{5} =
     3     9     5
HT_out{6} =
     3     9     5
     4     5     4
HT_out{7} =
     3     9     5
     3     2     7
HT_out{8} =
     3     9     5
     3     2     7
     4     5     4
HT_out{9} =
     9     7     2
HT_out{10} =
     9     7     2
     4     5     4
HT_out{11} =
     9     7     2
     3     2     7
HT_out{12} =
     9     7     2
     3     2     7
     4     5     4
HT_out{13} =
     9     7     2
     3     9     5
HT_out{14} =
     9     7     2
     3     9     5
     4     5     4
HT_out{15} =
     9     7     2
     3     9     5
     3     2     7
HT_out{16} =
     9     7     2
     3     9     5
     3     2     7
     4     5     4