Can someone explain this loop?

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Tri Dang
Tri Dang 2021-6-14
回答： Walter Roberson 2021-6-14
A = [0 1.7 2; 3 4 8; 4.2 3 8];
numEven = 0;
for k = 1:numel(A)
if mod(A(k),2) == 0
numEven = numEven+1;
end
end
Why numEven =5 ? Can someone explain? As I understand mod(A(k),2 == 0 is logical command therefore the sum of mod(A(k),2 supposed to be equal 5, and 5+1=6?
  2 个评论
SALAH ALRABEEI
SALAH ALRABEEI 2021-6-14
it counts the even numbers by checking the reminder of dividing by 2.
What is ur A!!
Tri Dang
Tri Dang 2021-6-14
Oh I editted the question
Can you check?
Thanks

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采纳的回答

Walter Roberson
Walter Roberson 2021-6-14
The count starts out 0. Then you start going through the array in linear index order. Each time you find an even number, you increase the count by 1.
The first 0 is even so you increase the count from 0 to 1
The 2 is even so you increase the count from 1 to 2
The 4 and 8 are even so you increase the count to 3 and then 4
The 8 is even so you increase the count from 4 to 5.
There is nothing in the code that would add 1 to the 5.
Another way of writing the code is
numEven = nnz(mod(A,2) == 0)
with no loops.

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