How to solve a function with different ranges

3 次查看（过去 30 天）
Delia Bosshart
Delia Bosshart 2021-6-15
编辑： Scott MacKenzie 2021-6-15
I have a variable that is composed of two functions for different ranges:
alfa_ox = 1/15*C_ox for 0 <= C_ox <= 15
alfa_ox = 1 for C_ox > 15
When I imply this in Matlab, it doesnt consider the second condition (that alfa can't be bigger than 1). How can I solve that?
C_ox = [16;15;7.5;2;7.5;15;15];
if C_ox > 15
alfa = 1
else alfa = 1/15.*C_02
end
Output:
alfa =
1.0667
1.0000
0.5000
0.1333
0.5000
1.0000
1.0000
  6 个评论
显示 4更早的评论
Delia Bosshart
Delia Bosshart 2021-6-15
Yes it is a vector. I could already solve the problem with the answers provided, thank you.
Scott MacKenzie
Scott MacKenzie 2021-6-15
编辑：Scott MacKenzie 2021-6-15
Sorry for the string of comments here, but your question uses the expression
1/15*C_ox
In your code we see
1/15.*C_02
Please clarify.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Star Strider
Star Strider 2021-6-15
Ran in:
alfa_fcn = @(C_ox) min(C_ox/15,1);
C_ox = [16;15;7.5;2;7.5;15;15];
alfa = alfa_fcn(C_ox)
alfa = 7×1
1.0000 1.0000 0.5000 0.1333 0.5000 1.0000 1.0000
.

更多回答（1 个）

Alan Stevens
Alan Stevens 2021-6-15
Ran in:
Try
C_ox = [16;15;7.5;2;7.5;15;15];
C_ox(C_ox<=15)=C_ox(C_ox<=15)/15;
C_ox(C_ox>15)=1
C_ox = 7×1
1.0000 1.0000 0.5000 0.1333 0.5000 1.0000 1.0000

类别

在 Help Center 和 File Exchange 中查找有关 Embedded Coder Supported Hardware 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by