Extracting elements from one matrix and placing in another

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Brian DeCicco
Brian DeCicco 2021-6-16
评论： Brian DeCicco 2021-6-16
Hello,
I have a matrix of size 97x97x117 (called yearly_array2). I'm trying to extract specific portions of the 3rd dimension (i.e. positions 7, 10, 34, 52, 79, 82, 88, 94, 100, & 115) and place those in a brand new matrix (called SLP_top_10). The expected size of the new matrix should be 1440x721x10. When I run the loop in my code, each iteration of "i" gets replaced by the next, and I'm left with the last postion (when i = 115) in the new matrix, when instead I want all 10 postions within my new matrix. What can I do, or how should I modify the following code, to retain all 10 positions of interest in my new array?
SLP_top_10 = zeros(97,97,10); %pre-allocating array of expected size
for i = [7 10 34 52 79 82 88 94 100 115] %positions of interest from yearly_array2
SLP_top_10 = yearly_array2(:,:,i);
end

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采纳的回答

Chunru
Chunru 2021-6-16
编辑：Chunru 2021-6-16
The following will do.
i = [7 10 34 52 79 82 88 94 100 115] %posi
SLP_top_10 = yearly_array2(:,:,i);
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Brian DeCicco
Brian DeCicco 2021-6-16
Thank you Chunru, it works now! That was really helpful...sometimes I try to overcomplicate things by creating loops when I don't have to.

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更多回答（2 个）

dpb
dpb 2021-6-16
MATLAB assigns the complete array to the LHS without having used subscrpting to indicate you want to place each plane extracted into a given new plane in the output array.
But, MATLAB also uses vector addressing so you "don't need no steenkin' loops!" at all.
iTop10 = [7 10 34 52 79 82 88 94 100 115];
SLP_top_10 = yearly_array2(:,:,iTop10);
David Hill
David Hill 2021-6-16
I am confused when you said the expected size was 1440x721x10 but then your code has the corrected expected size.
SLP_top_10=yearly_array2(:,:,[7 10 34 52 79 82 88 94 100 115]);%expected size 97x97x10

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