Finding integers between two vectors

2013 9 1
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hi
im new in the matlab world
i have 2 vectors A and B size (1xM)
i need to find all the integers betwwen corresponding Columns and store the integers in cell arry
for example:
A= 4.54 5.11 9.58 15.04
B= 1.01 3.2 5.5 16.98
i need to create cell arry X that each column contains all the integers between the numbers in A and B columns (1.01-4.54 the integers 2,3,4 3.2-5.11 the integers 4,5... )
X=
2 4 6 16
3 5 7
4 8
9
how can i do it?
thanks

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John Doe
John Doe 2013-9-1

0 个投票

A= [4.54 5.11 9.58 15.04];
B= [1.01 3.2 5.5 16.98];
C = sort([A; B]);
C(1,:) = ceil(C(1,:));
C(2,:) = floor(C(2,:));
temp = diff(C) + 1;
D = zeros(max(temp),size(C,2));
for ii = 1:size(C,2)
D(1:temp(ii),ii) = C(1,ii):C(2,ii);
end

3 个评论
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david
david 2013-9-2
编辑：david 2013-9-2
have a more difficult problem and I would be happy if you help me..
i have 4 Matrices in UV axis :
uv1=[umin; vmin; ones(size(P1U))];% (umin,vmin)
uv2=[umax; vmax; ones(size(P2U))];% (umax,vmax)
uv3=[umin; vmax; ones(size(P3U))];% (umin,vmax)
uv4=[umax; vmin; ones(size(P4U))];% (umax,vmin)
Each column in each matrix contains a coordinate(integers) ..all four matrices containing in each column coordinates that build a block i need to find all the integer coordinates in Each block and arrange them in two matrices one for U and one for V, Each column in U corresponds to the column in V
i added a link for picture: https://www.dropbox.com/s/bdvh6xzmjbyurhf/example.jpg
U=
1 5 8
2 6 0
3 7 0
4 0 0
V=
2 5 7
3 6 0
4 7 0
8 0 0
thanks
the cyclist
the cyclist 2013-9-2
编辑：the cyclist 2013-9-2
@david, I expect you realize this, since you accepted the answer, but this solution has two features that are different from what you specified in your question:
  • It is a numeric array, not a cell array.
  • It includes extra zeros.
Maybe that doesn't matter to you, but just in case another person tries to use this solution, it is good to realize.
the cyclist
the cyclist 2013-9-2
@david, I suggest you ask your second question as a brand-new one, rather than as a comment here. You will get more "traffic" seeing it.

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the cyclist
the cyclist 2013-9-1
编辑：the cyclist 2013-9-1

1 个投票

Here is a slick one-liner:
arrayfun(@(x,y) (ceil(min([x y])):floor(max([x,y])))',A,B,'UniformOutput',false)
Here is a straightforward way with a loop:
A = [4.54 5.11 9.58 15.04];
B = [1.01 3.2 5.5 16.98];
N = length(A);
X = cell(1,length(A));
for i = 1:N
hi = floor(max([A(i) B(i)]));
lo = ceil(min([A(i) B(i)]));
X{i} = (lo:hi)';
end

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