Loop to populate a 12 by 12 matrix

1 次查看（过去 30 天）
DARLINGTON ETAJE
DARLINGTON ETAJE 2021-6-24
评论： DARLINGTON ETAJE 2021-6-24
Hello Guys,
I am tryling to form a 12 by 12 matrix for 11 elements. I am getting some errors. Take a look at my code below: it looks perfect to me but it is not working
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1=zeros(12,1);
K2=zeros(12,1);
K3=zeros(12,1);
K4=zeros(12,1);
K5=zeros(12,1);
K6=zeros(12,1);
K7=zeros(12,1);
K8=zeros(12,1);
K9=zeros(12,1);
K10=zeros(12,1);
K11=zeros(12,1);
K12=zeros(12,1);
K=zeros(12,12);
for i=1:n
K1(i)=[SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2(i)=[0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3(i)=[0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4(i)=[0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5(i)=[0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6(i)=[0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7(i)=-K1;
K8(i)=-K2;
K9(i)=-K3;
K10(i)=-K4;
K11(i)=[0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12(i)=[0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K(i)=[K1(i) K2(i) K3(i) K4(i) K5(i) K6(i) K7(i) K8(i) K9(i) K10(i) K11(i) K12(i)];
end
  1 个评论
DARLINGTON ETAJE
DARLINGTON ETAJE 2021-6-24
Thank you so much Walter. It worked. You are an excellent person. The only challenge is that working with the code in struct is different than in a double.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2021-6-24
Ran in:
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1 = repmat({zeros(12,1)},n,1);
K2 = repmat({zeros(12,1)},n,1);
K3 = repmat({zeros(12,1)},n,1);
K4 = repmat({zeros(12,1)},n,1);
K5 = repmat({zeros(12,1)},n,1);
K6 = repmat({zeros(12,1)},n,1);
K7 = repmat({zeros(12,1)},n,1);
K8 = repmat({zeros(12,1)},n,1);
K9 = repmat({zeros(12,1)},n,1);
K10 = repmat({zeros(12,1)},n,1);
K11 = repmat({zeros(12,1)},n,1);
K12 = repmat({zeros(12,1)},n,1);
K = repmat({zeros(12,1)},n,1);
for i=1:n
K1{i} = [SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2{i} = [0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3{i} = [0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4{i} = [0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5{i} = [0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6{i} = [0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7{i} = -K1{i};
K8{i} = -K2{i};
K9{i} = -K3{i};
K10{i} = -K4{i};
K11{i} = [0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12{i} = [0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K{i} = [K1(i); K2(i); K3(i); K4(i); K5(i); K6(i); K7(i); K8(i); K9(i); K10(i); K11(i); K12(i)];
end
K
K = 11×1 cell array
{12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell}
K{1}
ans = 12×1 cell array
{12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double}
K{1}{1}
ans = 12×1
0.3563 0 0 0 0 0 -0.3563 0 0 0

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Statistics and Machine Learning Toolbox 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by