how to access zip files in the directory?

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sandy
sandy 2013-9-5
hi ..example.if i have a folder name as 'DATA',inside this subfolder namely A TO Z are ther..in this each folder(A TO Z),many .zip files are ther..i need to fetch all the .zip files inside main folder('DATA'),and extract them to a separate folder.is it possible? any defined function?

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Laurent
Laurent 2013-9-5
Using the 'dir'-command you can obtain a list of files.
In your case you could use something like:
filelist=dir('DATA/*.zip');
or
filelist=dir('DATA\*.zip');
depending on your OS.
Then filelist will be a struct in which filelist.name has the filenames.
'unzip' can then be used to unzip your files.
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sandy
sandy 2013-9-16
编辑：sandy 2013-9-16
this is the code i checked for my case,its not working
folder ='F:\test folder\';
for kk=2000:2013
if exist(folder,'dir')
for ll=1:12
if exist(folder,'dir')
for mm=1:31
currfold=[folder(mm) '\*.zip'];
currfiles=dir(currfold);
for jj=1:length(currfiles)
unzip([folder(ii) '\' currfiles(jj).name],outputfolder);
end
end
end
end
end
end
Laurent
Laurent 2013-9-16
You are always using 'folder' and are not adding the year, month or date, when you check if they exist. I would change it in something like this:
Be aware that I did not check this code, so there could be small errors/mistakes, but I hope you get the idea.
for kk=2000:2013
yearfolder=[folder num2str(kk) '\'];
if exist(yearfolder,'dir')
for ll=1:12
monthfolder=[yearfolder num2str(ll) '\'];
if exist(monthfolder,'dir')
for mm=1:31
currfold=[monthfolder num2str(mm) '\'];
if exist(currfold,'dir')
currfiles=dir([currfold '*.zip']);
for jj=1:length(currfiles)
unzip([currfold '\' currfiles(jj).name],outputfolder);
end
end
end
end
end
end
end

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