清空筛选条件
清空筛选条件

Using "bvp4c" to solve 2nd order DE?

3 次查看（过去 30 天）
Aaron
Aaron 2013-9-11
I was told that using a template and changing a few things would provide me with an answer to a 2nd order DE, using bvp4c. But I'm not sure how. I changed my low and high boundaries
function bvp4c
xlow = 0; xhigh = 10;
solinit = bvpinit(linspace(xlow,xhigh,10),[1 -1]);
sol = bvp4c(bvp4ode,bvp4bc,solinit);
xint = linspace(xlow,xhihg,20);
sxint = deval(sol,xint);
plot(xint,sxint(1,:))
function dydx = bvp4ode(x,y)
dydx = [y(2) y(1)];
function res = bvp4bc(ya,yb)
res = [ya(1) yb(1)]; % I think this is another area of concern.
Here is the initial data given: d^2T/dx^2 - 0.15T = 0 T(0) = 240 T(10) = 150
This is a bit confusing!!

请先登录，再回答此问题。

回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Boundary Value Problems 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by