I want to compare two arrays and check that which value is missing in second array as compared to first one?

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A=[ 0 1 1 ;
1 1 0 ];
target=[1 2 3 4];
[m,n]=size(A);
c1=0;cover1=[];sum_coord=[];sss=0;
for i=1:m
cc=0;t_coordinate=[];
for j=1:n
if A(i,j)==1
cc=cc+1;
t_coordinate(cc,:)=j;
sss=sss+1;
sum_coord(sss,:)=t_coordinate(cc,:);
end
end
display(t_coordinate)
end
sum_coord=sort(sum_coord);
sum_coord=unique(sum_coord);
display(sum_coord)
first array is "Target" and second is "sum_coord"....

采纳的回答

Rik
Rik 2021-7-4
编辑:Rik 2021-7-4
You should avoid variable names like sum, as that will prevent you from using the sum function.
Your question sounds like you need the ismember function. However, it is unclear how your code relates to the question in the title.
  3 个评论
Rik
Rik 2021-7-4
Did you try to google the documentation for the ismember function?
A=[ 0 1 1 ;
1 1 0 ];
target=[1 2 3 4];
[m,n]=size(A);
c1=0;cover1=[];sum_coord=[];sss=0;
for i=1:m
cc=0;t_coordinate=[];
for j=1:n
if A(i,j)==1
cc=cc+1;
t_coordinate(cc,:)=j;
sss=sss+1;
sum_coord(sss,:)=t_coordinate(cc,:);
end
end
end
sum_coord=sort(sum_coord);
sum_coord=unique(sum_coord);
disp(sum_coord)
1 2 3
L=ismember(target,sum_coord);
ismissing=target( ~L );
disp(ismissing)
4

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