How to solve a complicated equation?
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There is a Equation G. How to obtain the values of α and β when G=0?
G=-(-Omega^3*tau + (alpha + beta)*Omega)^2 - (Omega^2 - alpha*f)^2.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/677023/image.png)
The answer:
alpha = Omega^2*cos(Omega*tau)/f;
beta = Omega*(f*sin(Omega*tau) - Omega*cos(Omega*tau))/f.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/677028/image.png)
CAN anyone help me with this issue??? Thanks!!!
采纳的回答
David Goodmanson
2021-7-16
编辑:David Goodmanson
2021-7-16
Hi Cola,
Since there is one equation and two unknowns, it must be possible to define, say, beta in terms of alpha, where alpha can be anything. For G = 0 we have
(-Om^3*t + (a+b)*Om)^2 = -(Om^2 - a*f)^2
so
-Om^3*t + (a+b)*Om = +-*i*(Om^2 - a*f)
where there are obvious notational substitutions for Omega, tau, alpha, beta, and the +- choice gives two different solutions. Solving for b,
b = (1/Om)*( Om^3*t -a*Om +-i*(Om^2 - a*f) )
where 'a' can be anything. Solving instead for a (this does not give a different family of solutions, rather the same ones expressed differently) gives
a = (Om^3*t +-i*Om^2 -b*Om)/(Om +-i*f)
Here the sign in the denominator (+ or -) has to match the sign in the denominator, and b can be anything. The choice b = 0 gives the solutions from Star Strider.
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