find & replace data in array

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Pierre
Pierre 2013-9-17
Hi, I have two arrays.
A=[7 14 21 28 35 42 49 56 63 70 77 84 91]
B=[22 55]
I wanna find the number in A which is close to the number in B and to replace the number in A by the number in B. Finally, A will be
A=[7 14 22 28 35 42 49 55 63 70 77 84 91].
Is there any better and faster algorithm to solve this issue? Thanks

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采纳的回答

Roger Stafford
Roger Stafford 2013-9-17
[~,p] = min(abs(bsxfun(@minus,A,B')),[],2);
A(p) = B;
There is an inherent ambiguity possible in this problem. An element in A that happens to be the closest one to both of two different elements of B could legitimately be replaced by either B element. In the above algorithm it is always the later one in B that does the replacing in such cases.

更多回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-9-17
A=[7 14 21 28 35 42 49 56 63 70 77 84 91]
B=[22 55]
for k=1:numel(B)
[ii,ii]=min(abs(A-B(k)));
A(ii)=B(k);
end
Andrei Bobrov
Andrei Bobrov 2013-9-17
编辑：Andrei Bobrov 2013-9-17
A=[7 14 21 28 23 35 21 42 49 56 63 70 54 77 84 91]
B = [22 55]
M = abs(bsxfun(@minus,A,B'));
t = bsxfun(@eq,M,min(M,[],2));
add1 = bsxfun(@times,t,B');
A(any(t)) = add1(t)

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