How to create Gauss noise within the interval

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I have an interval with lower boundary at a = -0.005 and upper boundary b = 0.005. I need to create the Gauss white noise within this interval. For uniformly distributed pseudorandom numbers (generated by rand) it is clear e.g.:
r = a + (b-a).*rand(100,1);
however it does not work for randn function.I need some way how to produce the Gaussian noise in given interval. Is there any way how to do it?
thanks

采纳的回答

Image Analyst
Image Analyst 2013-9-17
One (inefficient) way is to just create more than you need and throw away any outside the range. Of course this might make it not purely Gaussian anymore
% Generate the numbers.
mu=2;
sigma = 4;
r = mu + sigma .* randn(1000,1);
% Define range we want
a = -7;
b = 9;
badNumbers = r < a | r > b;
r(badNumbers) = [];
numberOfElementsNow = numel(r)
% Define how many you need
numElementsNeeded = 400;
% Get them
if numElementsNeeded < numberOfElementsNow
r = r(1:numElementsNeeded);
numberOfElementsNow = numel(r)
else
% Tack some more on and try again.
end

更多回答(2 个)

Daniel Shub
Daniel Shub 2013-9-17
What you are looking for is typically called a Truncated Gaussian. There is a highly rated FEX:submission

Laurent
Laurent 2013-9-17
This is not possible, since the output of randn can be in principle any value between -Inf and +Inf.
Depending on what you want you could set the width of the gaussian to a reasonable value (for example sigma=0.005) and then later clip values outside of your interval to the border values.

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