how to create matrix with coordinates and calculate distance?
3 次查看(过去 30 天)
显示 更早的评论
n = 3; ri=0.9
source = 1;
destination = 3;
Link=(n*(n-1))/2;
c=2^Link;
NN = toeplitz(Link+1:-1:2)
mask = logical(fliplr(diag(ones(1,Link-1),-1)));
NN(mask) = 1;
for c = 0:2^Link-1
l = bitget(c, NN)
end
i have this type matrix code. l is the matrix.how to calculate distance.
i = 1 :n
j = i+1:n
D(i,j) = sqrt((x(i)-x(j))^2 + (y(i)-y(j))^2);
please help to calculate distance.
0 个评论
采纳的回答
Simon Chan
2021-7-9
[Ny, Nx] = size(l);
[X,Y]=meshgrid(1:Nx,1:Ny);
D = sqrt(X.^2 + Y.^2)
6 个评论
Simon Chan
2021-7-9
Sorry, no idea about interference. You may search previous questions to see whether you can get any solution from others.
更多回答(1 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!