Intersecting and non-intersecting box regions
10 次查看(过去 30 天)
显示 更早的评论
Having a set of bounding box values [x y width height] , how can i find the number of bounding box that gets intersected and that do not gets intersected when plotted
From the above example, there are 5 intersecting boxes and 2 non-intersecting boxes
How can i do so with the attached bounding box values
0 个评论
采纳的回答
Matt J
2021-7-10
编辑:Matt J
2021-7-10
Using rectint(), you can straightforwardly obtain a binary mask A such that A(i,j)=1 if rectangle bbx(i,:) and bbx(j,:) intersect.
load bbx
A=rectint(bbx,bbx)>0
and therefore the number of rectangles that have an intersection another rectangle would be,
N=sum(tril(A,-1),'all')
6 个评论
更多回答(2 个)
Simon Chan
2021-7-10
If viusal inspection is allowed, then the number can be counted by plotting the boxes in a figure:
rawdata=load('bbx.mat');
figure
for k=1:length(rawdata.bbx)
rectangle('Position',rawdata.bbx(k,:))
end
4 个评论
Simon Chan
2021-7-10
Would you please run the following commands before the above script:
clear;
clc;
If the error happens again, would you please run the following:
size(A) % Check the dimension of Matrix A
size(B) % Check the dimension of Matrix B
KSSV
2021-7-10
Run a loop for each box and find the intersection points. Use this to get the intersection points.
If your output is empty, it means there is no intersection.
3 个评论
KSSV
2021-7-10
You have origin, length and width of bounding box. So you can get four vertices of the box. You need to use four coordinates for each bounding box to get the intersection points.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrices and Arrays 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!