How can I code a two variable function?

2021 7 10
1 个回答
回答已采纳
更新时间：2021 7 11
2 次查看（30 天）

0 个投票

Hi, could you code this function from ?
I know I can't do it to infinity, so I choose the sum from 0 to 100. Please, help.
.

请先登录，再回答此问题。

 采纳的回答

ANKUR KUMAR
ANKUR KUMAR 2021-7-11
编辑：ANKUR KUMAR 2021-7-11
Ran in:

0 个投票

Ran in:
You can simply use for loop to iterate x and y. Refer to the below code just for your reference. You might need to make modification as per your need.
This might be the good starting point for you to write code independently.
Anyway, I am getting some of the NaN values.
func = @(n,x,y) (((-1)^n)/((2*n + 1)^3))* sech(((2*n + 1)*pi)/2)*cosh(((2*n + 1)*pi*x)/2)*cos(((2*n + 1)*pi*y)/2);
n_upper_limit=100;
for x=1:5
for y=1:5
u(x,y) = 1- y^2 - ((32)/(pi^3))*(sum(arrayfun(@(n) func(n,x,y), 1:n_upper_limit),'omitnan'));
end
end
disp(u)
1.0e+130 * -0.0000 -0.0000 -0.0000 -0.0000 -0.0000 -0.0000 1.6033 0.0000 -1.6033 -0.0000 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN
% For plotting u
imagesc(u)
title('Values of u')
xlabel('x values')
ylabel('y values')
xticks([1:5])
yticks([1:5])
colorbar
set(gca,'Ydir','normal')

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Interpolation 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by