Removing entries of vector indexed by odd integer.

11 次查看（过去 30 天）
David
David 2013-9-25
So, in a question we've been asked to define a vector "x" which begins at 1.5 and ends at -3.5 with 101 entries in between without the use of any loops. So, I used linspace(1.4, -3.5, 101) to do this. However the next part of the question requires you to create a matrix "y" which corresponds to "x" only with the entries indexed by an odd integer removed. How can you do this without using a loop? Is there a function for it? Thanks.

请先登录，再回答此问题。

采纳的回答

Leah
Leah 2013-9-25
You just have to reference every other element of the vector you created.
x=linspace(1.4, -3.5, 101) ;
y=x(1:2:end);
  1 个评论
David
David 2013-9-25
Will that not include elements 1 and 101 though, and they're odd indexes? Why wouldn't it be y = x(2:2:100);?

请先登录，再进行评论。

更多回答（1 个）

Matt J
Matt J 2013-9-25
编辑：Matt J 2013-9-25
x=linspace(1.4, -3.5, 101) ;
y=x;
y(1:2:end)=[];
or
y=x(2:2:end);
  9 个评论
显示 7更早的评论

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Functional Programming 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by