Reading data into a structure

2 次查看（过去 30 天）
Edward
Edward 2013-9-26
回答： Walter Roberson 2013-9-26
Hi, im reading the file:
26/09/2013,16:04:40 2412 928.0 49.94930
25/09/2013,14:24:30 2412 914.0 -999999
using:
fid = fopen('/path/to/your/file.txt', 'rt');
output = textscan(fid, '%s %s %f %f %f', 'Delimiter', ' ,');
fclose(fid);
now i want to read this into an array of structures s. I have tried using the following:
s.date = output{1};
s.time = output{2};
etc
however this gives me size(s) = 1 (a single structure with arrays of dates and times as members) I would prefer to have an array of structures each with a single date and time. Is this possible?

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2013-9-26
[s{1>length(output{1})}.date] = [output{1}{:}];
[s{:}.time] = [output{2}{:}];

更多回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-9-26
编辑：Azzi Abdelmalek 2013-9-26
%That's what you have
y=1:10
s.date=y
%result
s =
date: [1 2 3 4 5 6 7 8 9 10]
%and you want
s=struct('date',num2cell(y))
%result
s =
1x10 struct array with fields:
date

类别

在 Help Center 和 File Exchange 中查找有关 Data Import and Export 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by