Neglecting difference between two values if it is very small so that value1= value2

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Cutie 2021-7-28

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评论： Fangjun Jiang 2021-7-29

I am working on a dataset. After some eigendecompostion process. I realise the difference between my values are as small as 1.8097e-14 which is my further implementation process.

Example

data1(1:10) = 0 0.1502 0.2970 0.4371 0.5673 0.6845 0.7863 0.8702 0.9343 0.9773

data2(1:10) = -0.0000 0.1502 0.2970 0.4371 0.5673 0.6845 0.7863 0.8702 0.9343 0.9773

C= data1(1:10)-data2(1:10)

C =

1.0e-12 *

0.0862 0.1227 0.1545 0.0772 0.1019 0.1178 -0.0174 0.0048 0.0170 0.0181

How do I code that the these difference be neglected so that values in data1 & data2 will be equal since the difference is very small

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回答（1 个）

Fangjun Jiang 2021-7-28

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编辑：Fangjun Jiang 2021-7-28

To compare element by element, abs(C) < Tolerance

To compare the two vectors as a whole, all(abs(C) < Tolerance)

or use

ismembertol(C,0,Tolerance)

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Cutie 2021-7-29

@Fangjun Jiang will it look like

if abs(Data1-Data2)<1e-6

Data1=Data2

end

Fangjun Jiang 2021-7-29

I guess you could to that. The solution is clear, do whatever to get the result you need.

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MATLAB Mathematics Fourier Analysis and Filtering

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R2021a

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