Using cell array for indexing

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Lionel Pöffel
Lionel Pöffel 2021-8-2
评论： Lionel Pöffel 2021-8-2
I have matrices of varying dimensionality I need to index.
So just writing A(i1,...,in) is not an option because n can vary in my application.
What is known to work for getting a single element out of A is using a cell array:
IndArray={i1,...,in}
Elem=A(IndArray{:})
However I'd like to do something like SubMatrix= A(i1,i2,...,im,:,:,...,:), where m<n. Is there a way to do that?
The following does not work:
IndArray={i1,...,im}
SubMatrix=A(IndArray{:})
Thanks in advance for any hints.

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采纳的回答

Rik
Rik 2021-8-2
I would suggest something like this:
IndArray={i1,...,im}
for dim=(numel(IndArray)+1):ndims(A)
IndArray{dim}=1:size(A,dim);
end
SubMatrix=A(IndArray{:})

更多回答（2 个）

Stephen23
Stephen23 2021-8-2
编辑：Stephen23 2021-8-2
No need for a loop, here is the simple and efficient MATLAB approach:
IndArray = {i1,..,im};
IndArray(1+end:ndims(A)) = {':'};
SubMatrix = A(IndArray{:})
How it works: MATLAB always allows a scalar element on the RHS to be allocated to any number of elements on the LHS. This applies to any array class: numeric, cell (as above), char, string, struct, etc.
  1 个评论
Lionel Pöffel
Lionel Pöffel 2021-8-2
Hello Stephen,
thanks for your answer. That is, of course, an additional improvement.

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Lionel Pöffel
Lionel Pöffel 2021-8-2
Hi Rik, that seems to work, thanks.
DGM posted an answer that surprisingly also seems to work but unfortunately deleted it (thanks to him/her as well).
For completeness I will note it here:
IndArray={i1,...,im}
for dim=(numel(IndArray)+1):ndims(A)
IndArray(dim)={':'};
end
SubMatrix=A(IndArray{:})
  1 个评论
DGM
DGM 2021-8-2
Sorry about that. I tried reading your other posts to try to figure out what exactly you were trying to do and had the feeling that I had misunderstood the intent.

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