a loop that checks for missing decimals in a vector, but it only runs once

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Mads Albertsen
Mads Albertsen 2021-8-5
评论： Mads Albertsen 2021-8-11
if want it to remove the numbers if it doesnt have 1.1, 1.2, 1.3 and so on up til 5 but it only runs once
v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
length(y)
for i = length(v)
c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
length(y)
if length(y) < 3
v(y)=[];
c = c+1;
else
c = c+1;
end
end

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回答（1 个）

Awais Saeed
Awais Saeed 2021-8-5
I think you want to delete elemetns of vector c from vector v. If that is what you want then you can do it as shown below
v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
for col = length(y):-1:1 % You must do this in reverse order as the size of vector v will keep changing
idx = y(col);
v(idx) = [];
end
  2 个评论
Rik
Rik 2021-8-5
Ran in:
If that is the goal you can do it in one go:
v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
L=ismember(v,c);
v(L)=[]
v = 1×10
2.2000 2.3000 4.2000 5.1000 3.2000 5.3000 3.3000 2.1000 5.2000 3.1000
Mads Albertsen
Mads Albertsen 2021-8-11
i figured it out, was just missing i = 1:length(v) since i need c to check for all the numbers uptil 5, so 4.2 also is removed since it is missing 4.1 and/or 4.3, sorry for being unclear

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