a loop that checks for missing decimals in a vector, but it only runs once

Question

Mads Albertsen 2021-8-5

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/892847-a-loop-that-checks-for-missing-decimals-in-a-vector-but-it-only-runs-once

评论： Mads Albertsen 2021-8-11

if want it to remove the numbers if it doesnt have 1.1, 1.2, 1.3 and so on up til 5 but it only runs once

v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
length(y)
for i = length(v)
    c = [1.1, 1.2, 1.3 ];
    y = find(ismember(v,c));
    length(y)
    if length(y) < 3
        v(y)=[];
        c = c+1;
    else
    c = c+1;
    end
end

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Rik 2021-8-5

What are you actually trying to do? Your code is uncommented and your single line description is not clear to me.

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Answer 1

Awais Saeed 2021-8-5

0
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https://ww2.mathworks.cn/matlabcentral/answers/892847-a-loop-that-checks-for-missing-decimals-in-a-vector-but-it-only-runs-once#answer_761527

在 MATLAB Online 中打开

I think you want to delete elemetns of vector c from vector v. If that is what you want then you can do it as shown below

v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
y = find(ismember(v,c));
for col = length(y):-1:1    % You must do this in reverse order as the size of vector v will keep changing
	idx = y(col);
	v(idx) = [];
end

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Rik 2021-8-5

在 MATLAB Online 中打开

If that is the goal you can do it in one go:

v = [1.3, 2.2, 2.3, 4.2, 5.1, 3.2, 5.3, 3.3, 2.1, 1.1, 5.2, 3.1];
c = [1.1, 1.2, 1.3 ];
L=ismember(v,c);
v(L)=[]
v = 1×10
    2.2000    2.3000    4.2000    5.1000    3.2000    5.3000    3.3000    2.1000    5.2000    3.1000

Mads Albertsen 2021-8-11

i figured it out, was just missing i = 1:length(v) since i need c to check for all the numbers uptil 5, so 4.2 also is removed since it is missing 4.1 and/or 4.3, sorry for being unclear

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