histc problem

3 次查看（过去 30 天）
Mohammad Golam Kibria
Hi, I have a matrix as follows:
I =
1 1 1 8 8 1 2
1 8 8 8 8 2 1
1 8 8 8 2 1 1
1 8 8 8 1 1 1
2 2 2 1 1 1 1
2 2 2 1 1 1 1
then the following code give me a error:
index= I==8; histc(index(:),1)
gives the follwing error.
??? Error using ==> histc First input must be non-sparse numeric array.
How to solve this?
Thanks

请先登录，再回答此问题。

回答（1 个）

Walter Roberson
Walter Roberson 2011-6-7
I'm not sure what you think you are going to accomplish with that, but
index = 0 + (I==8);
histc(index(:),1)
  2 个评论
Mohammad Golam Kibria
Mohammad Golam Kibria 2011-6-7
your code give the proper output that i want.but why the following syntax is necessary:
index = 0 + (I==8);
Mohammad Golam Kibria
Mohammad Golam Kibria 2011-6-7
actually I have tow matrix I and I1.
I have some values having 1. and I1 is a binary matrix having
0 and 1. I need two know how many 1s are there in I1 where
the values of I have 1s. Is there any easy code

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by