circshift() one number ,in each iteration?

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Mary Jon 2013-10-6

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https://ww2.mathworks.cn/matlabcentral/answers/89319-circshift-one-number-in-each-iteration

评论： Image Analyst 2013-10-6

can I am do shifting the number A(2,1) of matrix (A) ,one times in each iteration,('iter=0' ,iter=iter+1)? how can do that?

A=[1 2 3;4 5 6;7 8 9]
% Shift A(2,1)
for k=1:size(A,2)-1
A(2,:)=circshift(A(2,:),[0 1])
end

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Azzi Abdelmalek 2013-10-6

That's what the code is doing

Image Analyst 2013-10-6

It shifts the entire second row one element at each iteration of the loop. Is that not what you wanted? Did you want to shift only the (2,1) element and not all of the elements in the second row? Either way, why? Seems like a funny thing to do unless it's homework or something. But it can't be homework because you would have tagged it as homework, so why do you want to do this?

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Azzi Abdelmalek 2013-10-6

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/89319-circshift-one-number-in-each-iteration#answer_98758

在 MATLAB Online 中打开

Maybe you want to save all the results

clear
A=[1 2 3;4 5 6;7 8 9]
% Shift A(2,1)
for k=1:size(A,2)-1
A(2,:)=circshift(A(2,:),[0 1])
out{k}=A
end
celldisp(out)

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Mary Jon 2013-10-6

isnt it? that mean E(20,1) at row number 20,column number 1,

I am want shifting it (2:33),with save all the result not last result only

Image Analyst 2013-10-6

编辑：Image Analyst 2013-10-6

size(array, n) means the length of array in the nth dimension. It DOES NOT mean array(n) which is the value of the array at index n. They're totally different things. By the way, you never answered my question in the comment at the very top.

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