Could I extract an specific column from a table and then use it in a loop without name it (variable)?
1 次查看(过去 30 天)
显示 更早的评论
I'm wondering if I can use directly the column (extracted from a matrix) inside the loop, for example or should I name if first because T1(:,8)(i) does not work
A = zeros(length(T1(:,7)),length(T2(:,7)));
for i=1:length(T1(:,7))
for ii=1:length(T2(:,7))
idx(i,ii) = ( abs((T1(:,8)(i)-T2(:,8)(i))))
end
end
0 个评论
采纳的回答
Walter Roberson
2021-8-15
h1 = height(T1); h2 = height(T2);
A = zeros(h1, h2);
for i = 1 : h1
for ii = 1 : h2
A(i,ii) = abs(T1{i,8} - T2{i,8});
end
end
However... you might as well use
A = abs(T1{:,8} - T2{:,8}.');
with no loop, provided you have R2015b or later.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!