How I can combine this cell values in a single matrix?

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Sourasis Chattopadhyay
评论： Simon Chan 2021-8-17
I want to get my output in (12X28) matrix
How I can get in a single (12X28) matrix
  2 个评论
Simon Chan
Simon Chan 2021-8-16
If the size of the first cell is [5x7 double], you may combine them to become a (12x7) matrix because all of them have 7 columns only.
Or you would like to repeat the cells until the final one has 28 columns?
Sourasis Chattopadhyay
Sourasis Chattopadhyay 2021-8-17
First cell is [1X7 double].
I am looking for (12X28) = Row(1*3*2*2) and Column (7+7+7+7).
as example,

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回答（2 个）

Wan Ji
Wan Ji 2021-8-16
If X{1} is 1x7 array, the simplest way is
matrixOut = cell2mat(X')
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显示 4更早的评论
Wan Ji
Wan Ji 2021-8-17
If your rowNum is a variable, is it calculated in this way?
RowNum = prod(arrayfun(@(i)size(X{i},1), 1:1:numel(X)))
Then
RowNum =
12
The whole code my be
RowNum = prod(arrayfun(@(i)size(X{i},1), 1:1:numel(X)));
X = arrayfun(@(i)repmat(X{i},RowNum/size(X{i},1),1), 1:1:numel(X), 'uniform', 0);
A = cell2mat(X) % A is what you want

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Simon Chan
Simon Chan 2021-8-17
编辑：Simon Chan 2021-8-17
Something like this and final matrix is C
clear; clc;
X = cell(1,4);
X{1} = round(10*rand(1,7));
X{2} = round(10*rand(3,7));
X{3} = round(10*rand(2,7));
X{4} = round(10*rand(2,7));
B{1} = repmat(X{1},12,1);
B{2} = repmat(kron(X{2},ones(2,1)),2,1);
B{3} = repmat(X{3},6,1);
B{4} = kron(X{4},ones(6,1));
C = cell2mat(B);
  2 个评论
Sourasis Chattopadhyay
Sourasis Chattopadhyay 2021-8-17
If my cell size is cange in this case It is not possiable to do by manually . In case my cell size is (mXn) ,then what should I do?
Simon Chan
Simon Chan 2021-8-17
Need to know the pattern how to repeat the matrix. If a pattern can be found, it is able to implement it in a loop.
However, I am also confused since the repeating method of a 2 rows matrix may be different (The left and right matrix in your elaboration).

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