How do I join a single string with multiple strings?

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Tom Wright
Tom Wright 2013-10-17
评论： Tom Wright 2013-10-17
Hi, I know I can do this with loops but there must be a nicer way.
basepath='/data/';
filebase='video_';
fileext='.avi';
files=['00a' '00b' '00c'];
I'd like the output to be the vector
['/data/video_00a.avi' '/data/video_00b.avi' '/data/video_00c.avi']
(although I'd also be happy with a vertical matrix.
Thanks Tom
  1 个评论
Matt Kindig
Matt Kindig 2013-10-17
编辑：Matt Kindig 2013-10-17
Are you sure you don't want 'files' to be a cell array? Because the way you've defined files, it will just concatenate 00a, 00b, etc. as one string. Observe:
files=['00a' '00b' '00c']
% files = '00a00b00c'
This is probably less useful to you. Instead, define 'files' as:
files = {'00a', '00b', '00c'}

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-10-17
编辑：Azzi Abdelmalek 2013-10-17
basepath='/data/';
filebase='video_';
fileext='.avi';
files={'00a', '00b', '00c'}
cellfun(@(x) sprintf([basepath filebase '%s' fileext],x),files,'un',0)
Look at
doc cell

更多回答（1 个）

Vivek Selvam
Vivek Selvam 2013-10-17
Here you go, Tom.
basepath = '/data/';
filebase = 'video_';
fileext = '.avi';
files = ['00a'; '00b'; '00c'];
n = size(files,1);
horzcat(repmat(basepath,n,1), repmat(filebase,n,1), files, repmat(fileext,n,1))

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