Line graph help required.
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I'm using Matlab for academic purposes to create a series of line graphs to display a set of x and y data and I have a couple of questions about Matlab that I would really appreciate if someone could clear up for me.
1. I replicated the ode23tx.m file and was wondering how the file marks each plot point with a circle (I have included a screenshot of this if I have not described it properly.)
2. Is there any way of ignoring the solution presented and show the error graph instead?
Thanks
3 个评论
dpb
2013-10-23
I'm thinking you've got a misconception on what [T,Y] are/represent in the ode23x documentation (and the same concept applies throughout Matlab as well as virtually all procedural programming languages for that matter).
They're "dummy" arguments; what they are named is completely immaterial to the use of the routine -- they take internally the value of the variable passed to them.
If you're integrating over space instead of time, the routine doesn't care; call it with
[x,y] = ode23t(ODEFUN,[xo xend],y0);
and that you've got a range of x's in place of the documented TSPAN is totally immaterial -- inside the function the t's are the x values.
回答(1 个)
Walter Roberson
2013-10-23
The ode routines plot the result if you do not assign the output to a variable.
There are also various hooks in the options structure that can be used to plot various items. Kyle, you should have a look at odeset()
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dpb
2013-10-23
Oh, good catch, Walter...I " never " use them w/o an output variable so forgot about the default behavior.
@Kyle...the actual question then is the circles on the lines comes from within odeplot with the following code snippet therefrom...
if ~ishold
ud.lines = plot(ud.t(1),ud.y(1,:),'-o');
hold on
ud.line = plot(ud.t(1),ud.y(1,:),'-o',EraseMode{:});
hold off
set(TARGET_AXIS,'XLim',[min(t) max(t)]);
else
ud.lines = plot(ud.t(1),ud.y(1,:),'-o',EraseMode{:});
ud.line = plot(ud.t(1),ud.y(1,:),'-o',EraseMode{:});
end
The 'o' on the '-o' is the culprit responsible...
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