Given hole diameter a, and outermost diameter b, determine the volume y of the resulting donut.
I think the input are the radii, not the diameters, but I'm too lazy to check for sure.
not really, the test sequence is simply wrong.
I spend 20mn to understand that the data are inverted, thanks :|
and also five minus it is not diameter but radii, a is outer radii and b the radii of the hole
It should be specified more clear what the input parameters mean exactly geometrically.
What a waste! Calling a radius a diameter. I got numbers that were off by a factor of 8, which turned out to be that I had used the information that a and b were diameters, whereas Bistwas used them as radii. Please correct the problem definition.
If a is the hole diameter and b is the outermost diameter, how can a>b in the test cases?
Problem is written incorrectly.
test suite'answer is wrong if a and b is diameter instead of radius.
Very good.
Good question.
Volume should be y = pi^2/32*(a+b)i*(b-a)^2
I wonder whether it it adequate to test correctness of double answers by equality. To do so discounts rounding errors and the fact that IEEE 754 does not guarantee the laws of arithmetic.
So, when you say "diameter" you mean "radius"? And when you say "outer" you mean "inner"?
If a is the hole diameter and b is the outermost diameter, how can a>b in the test cases?
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