Tanya, you like triangles.
Good one
Nice one
Pythagoras theorem
These are interesting
a = sqrt(c^2-b^2);
good question
this isn't a calculation!
lol
what the
ez
test_1 a=sqrt(3) is longer than b=1
the good solution would be
a= min(sqrt(c^2 -b^2),b)
instead
regexp cheat
Kudos for finding this solution - it did indeed meet all the test cases, but wasn't quite what I had in mind! I will add a new test.
341 Solvers
Flag largest magnitude swings as they occur
588 Solvers
498 Solvers
467 Solvers
1226 Solvers
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!