Problem 2397. Leap Year
According to Gregorian Calender(which is in use now, in many countries),decide whether a given year is a leap year or not. Give 'true' if the given year is a leap year and 'false',if not.
Note: In the Gregorian calendar 3 criteria must be taken into account to identify leap years:
The year is evenly divisible by 4; If the year can be evenly divided by 100, it is NOT a leap year, unless; The year is also evenly divisible by 400. Then it is a leap year.
Solution Stats
Problem Comments
- 
		3 Comments
 
Kumar, in problem #4 there is one to many right parenthesis. George...
Actually I just realized it is the "isequal" is missing in test #4.
Thanks George.Am extremely sorry for that.I just corrected it.
Solution Comments
Show commentsProblem Recent Solvers188
Suggested Problems
- 
         
Getting the absolute index from a matrix
251 Solvers
 - 
         
         
9693 Solvers
 - 
         
Celsius to Fahrenheit converter
647 Solvers
 - 
         
         
541 Solvers
 - 
         
         
627 Solvers
 
More from this Author1
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!