Problem 240. Project Euler: Problem 6, Natural numbers, squares and sums.
The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2 = 55^2 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.
Find the difference between the sum of the squares of the first N (where N is the input) natural numbers and the square of the sum.
Thank you to Project Euler Problem 6
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A problem where one must be at least a little careful about floating point arithmetic. It might have been interesting if one of the test cases were x=1e5 or larger. Even more interesting if the execution time were a factor in the "score". These factors might impact how the problem would be best solved.
@ Doug Hall, I have solved all the problems in the series. However, I have not received the badge and the associated scores on completion of the series. Can you please look into this?
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