Write a function f = counter(x0,b) to construct a counter handle f that counts with an initial value x0 and a step size b.
E.g.,
>> f = counter(0,1) % Initialize a counter f() with initial_count = 0 and step_size = 1
>> f()
ans =
0
>> f()
ans =
1
>> f()
ans =
2
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My function works directly as described - but does not manage to pass the test suite ... what is wrong?
%%
function varargout = counter(varargin)
persistent add base
if isempty(varargin)
base = base + add;
varargout{1} = base;
end
if numel(varargin) > 1
add = varargin{2};
base = varargin{1}-add;
end
end
For anyone needing a gentle refresher (like I did) on nested anonymous functions:
https://www.mathworks.com/matlabcentral/cody/problems/24-function-iterator
Cody's Problem 24 might be of relevance, but note that so far very few of the correct solutions to the present problem (Problem 44345) have used anonymous functions, whereas all of the correct solutions have used named functions (some nested, some not).
Correction: there is a solution here (Solution 1308690) which only uses an anonymous function, without calling a named user function.
Either (or both) of the following pages may be of interest in tackling this problem: https://mathworks.com/help/matlab/matlab_prog/nested-functions.html and https://mathworks.com/help/matlab/matlab_prog/share-data-between-workspaces.html .
It's the best problem in Cody:Easy
You can also use class definition to solve it, amazing!
the tests can be strengthened a bit, to allow multiple counters
g = counter(1,2);
h = counter(3,5);
assert(isequal([1 3 5 3 8 13], [g() g() g() h() h() h()]));
:
One way to solve this problem:
https://paste.ubuntu.com/p/nCFk9p7XNM/