Problem 44947. Find the Oldest Person in a Room

Created by Pooja Lalan

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Solve

Solution Stats

23295 Solutions
6291 Solvers

Last Solution submitted on Apr 21, 2021

Last 200 Solutions

Problem Comments

7 Comments

7 Comments

Show 4 older comments

Renato SL on 3 Sep 2019

In the first test suite, Robinson and Reed both have the same age, so I think either the test suite should be improved or Reed's age in the .mat file should be changed.

Anubhav Chaubey on 13 May 2020

Tricky question though

Sivaramarao B on 7 Jun 2020

Good one

Gregory Bohorquez on 2 Jul 2020

I don't understand, how to solve this problem.
Can someone help me?

Manoj Kumar Koduru on 30 Nov 2020

This may helps
[~,Id]=max(age)
old_name=name(Id)

Hari Prasad on 21 Dec 2020

function old_name = find_max_age(name,age)
[M I]=max(age)
old_name = name(I)
end
hope this will be helpfull :)

rh x on 6 Apr 2021 at 6:57

function old_name = find_max_age(name,age)
[x,y]=max(age,[],2);
old_name=name(y);
end
who can help me,it ran incorrectly

Solution Comments

Solution 4847662

1 Comment

1 Comment

Md.Emtiajul Islam on 16 Feb 2021

simple indexing problem

Solution 4143880

1 Comment

1 Comment

Cory Cunningham on 11 Dec 2020

Tough problem

Solution 3832283

1 Comment

1 Comment

LIFE on 25 Nov 2020

its good

Solution 2649605

1 Comment

1 Comment

JOSE ANTONIO BUTENEGRO GARCIA on 3 Jul 2020

Keep in mind you have to obtain the position for the older person. This was taught in the max(var) class. Good luck!

Solution 2257445

2 Comments

2 Comments

VINAY SINNUR on 6 May 2020

tricky

SHIVANI CHORGE on 22 May 2020

fist find maximum age then use index of maximum age and by using that find corresponding name

Solution 2244218

1 Comment

1 Comment

srisai vangara on 29 Apr 2020

good one.

Solution 1937419

1 Comment

1 Comment

Omkar Chavan on 8 Apr 2020

Even typing only "Old_name = 2" resuts in size to be 13. What logic and language did you apply for getting size 8?

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function indexing

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Problem 44947. Find the Oldest Person in a Room

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Problem 44947. Find the Oldest Person in a Room

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